WEBVTT
1
00:00:00.270 --> 00:00:05.030 A:middle L:90%
Let's use a graph of the sequence and to predict
2
00:00:05.030 --> 00:00:10.060 A:middle L:90%
weather, a convergence or diverges. Now look here
3
00:00:10.060 --> 00:00:11.779 A:middle L:90%
and gizmos. We have a graph. You could
4
00:00:11.779 --> 00:00:16.489 A:middle L:90%
see our formula for am. Now we've graft the
5
00:00:16.489 --> 00:00:22.710 A:middle L:90%
first seventy six terms, and based on the looks
6
00:00:22.890 --> 00:00:24.890 A:middle L:90%
, it looks like this thing does not converge.
7
00:00:25.739 --> 00:00:28.530 A:middle L:90%
But it's more or less bouncing around between negative one
8
00:00:28.530 --> 00:00:43.969 A:middle L:90%
one. So Betweennegative one and and one sense the
9
00:00:43.969 --> 00:00:48.420 A:middle L:90%
limit. It's and goes to infinity of n squared
10
00:00:48.420 --> 00:00:51.850 A:middle L:90%
over one plus and squared equals one, sir,
11
00:00:52.439 --> 00:00:59.780 A:middle L:90%
So A N is approximately equal to co sign in
12
00:01:00.740 --> 00:01:07.290 A:middle L:90%
for a large and and the limit of co sign
13
00:01:07.290 --> 00:01:21.049 A:middle L:90%
n does not exist. Therefore, a N is
14
00:01:22.239 --> 00:01:27.959 A:middle L:90%
divergent again. It's diversion because its limit doesn't exist
15
00:01:29.180 --> 00:01:30.349 A:middle L:90%
, and that's our final answer.